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26x^2=56
We move all terms to the left:
26x^2-(56)=0
a = 26; b = 0; c = -56;
Δ = b2-4ac
Δ = 02-4·26·(-56)
Δ = 5824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5824}=\sqrt{64*91}=\sqrt{64}*\sqrt{91}=8\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{91}}{2*26}=\frac{0-8\sqrt{91}}{52} =-\frac{8\sqrt{91}}{52} =-\frac{2\sqrt{91}}{13} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{91}}{2*26}=\frac{0+8\sqrt{91}}{52} =\frac{8\sqrt{91}}{52} =\frac{2\sqrt{91}}{13} $
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